Guides / Equations
Solving equations with fractions: clear the denominators first
Short answer
Find the least common denominator (LCD) of every fraction in the equation. Multiply every term on both sides by it, including terms that aren't fractions. The denominators cancel, and you're left with an equation with no fractions to solve the usual way. Put parentheses around any numerator with more than one term before you multiply.
Why it works
You can multiply both sides of an equation by the same non-zero number without changing its solutions. If you choose a number every denominator divides into, each fraction turns into a whole-number expression. Working with 4x + 3x = 84 is much easier than working with twelfths.
Example 1: x/3 + x/4 = 7
The denominators are 3 and 4. The LCD is 12.
- x3 + x4 = 7Start.
- 12 · x3 + 12 · x4 = 12 · 7Multiply every term by 12, including the 7.
- 4x + 3x = 8412 ÷ 3 = 4 and 12 ÷ 4 = 3.
- 7x = 84Combine like terms.
- x = 12Divide by 7.
Check: 12/3 + 12/4 = 4 + 3 = 7.
Example 2: numerators with more than one term
Solve x + 12 − x − 23 = 2. The LCD of 2 and 3 is 6.
- x + 12 − x − 23 = 2Start.
- 3(x + 1) − 2(x − 2) = 12Multiply every term by 6. Keep the numerators in parentheses.
- 3x + 3 − 2x + 4 = 12Distribute. −2 times −2 is +4.
- x + 7 = 12Combine like terms.
- x = 5Subtract 7.
Check: (5 + 1)/2 − (5 − 2)/3 = 3 − 1 = 2.
Example 3: a variable in the denominator
Solve 3x + 12 = 54. The LCD is 4x. Because x is in a denominator, x can't be 0, so note that before you start.
- 3x + 12 = 54Start. x ≠ 0.
- 12 + 2x = 5xMultiply every term by 4x: 4x · 3/x = 12, 4x · 1/2 = 2x, 4x · 5/4 = 5x.
- 12 = 3xSubtract 2x.
- x = 4Divide by 3. It isn't 0, so it's allowed.
Check: 3/4 + 1/2 = 3/4 + 2/4 = 5/4.
Always check answers when the variable is in a denominator. Multiplying by an expression like x − 2 can produce an answer that makes a denominator zero. For example, clearing xx − 2 = 2x − 2 + 3 gives x = 2, which isn't allowed, so that equation has no solution.
Common mistakes, and the exact line they happen on
1. Forgetting to multiply the terms that aren't fractions
- x3 + 2 = 5Start.
- x + 2 = 15This is the mistake. The x/3 and the 5 were multiplied by 3, but the 2 wasn't.
- x = 13Checking: 13/3 + 2 isn't 5.
- x + 6 = 15Correct: 3 · 2 = 6.
- x = 9Check: 9/3 + 2 = 5.
Multiplying “both sides” means multiplying each whole side, and each side here is a sum. Every term on it gets multiplied.
2. Losing a sign after a subtracted fraction
Back to Example 2. Without parentheses, the minus sign only reaches the first term of the second numerator:
- 3(x + 1) − 2(x − 2) = 12Fine so far.
- 3x + 3 − 2x − 4 = 12This is the mistake. −2 · (−2) is +4, not −4.
- x = 13Checking: 14/2 − 11/3 isn't 2.
The fraction bar works like parentheses. When you clear it, write the parentheses in so the minus sign reaches every term.
3. Cross-multiplying when there are more than two fractions
Cross-multiplication is a shortcut for exactly one fraction on each side, like ab = cd. With three terms, as in Example 1, it doesn't apply. Multiplying by the LCD always works, including when there's one fraction on each side.
Practice
Solve x5 − 1 = 3.
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Multiply by 5: x − 5 = 15, so x = 20.
Solve x2 + x3 = 10.
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LCD 6: 3x + 2x = 60, so x = 12.
Solve 2x − 13 = x + 42.
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LCD 6: 2(2x − 1) = 3(x + 4), 4x − 2 = 3x + 12, so x = 14. Check: 27/3 = 9 and 18/2 = 9.
Solve x − 34 − x + 16 = 1.
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LCD 12: 3(x − 3) − 2(x + 1) = 12, 3x − 9 − 2x − 2 = 12, x − 11 = 12, so x = 23. Check: 20/4 − 24/6 = 5 − 4 = 1.
Solve 2x + 13 = 1.
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LCD 3x (x ≠ 0): 6 + x = 3x, so x = 3. Check: 2/3 + 1/3 = 1.
Solve x4 + 12 = x3.
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LCD 12: 3x + 6 = 4x, so x = 6. Check: 6/4 + 1/2 = 2 and 6/3 = 2.